Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.5 - Lines and Planes in Space - Exercises 12.5 - Page 727: 23



Work Step by Step

The plane passing through the points $(1,1,-1),(2,0,2), (0,-2,1)$ Now, $\overrightarrow{a}=\lt 1,-1,3 \gt; \overrightarrow{b}=\lt -1,-3,2 \gt$ and $\overrightarrow{a}\times \overrightarrow{b}=\lt -1,-3,2 \gt= 7i-5j-4k$ Suppose the equation of plane is $7x-5y-4z=D$ For point $(1,1,-1)$: $ 7(1)-5(1)-4(-1)=d \implies d=6 $ Hence, $7x-5y-4z=6$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.