Chapter 12: Vectors and the Geometry of Space - Section 12.5 - Lines and Planes in Space - Exercises 12.5 - Page 727: 34

$3$

The distance formula for two vectors can be calculated as: $d=\dfrac{|p \times q|}{|q|}$ and $p \times q=\lt -13,16,5\gt $ so,$|p \times q|=\sqrt{(-13)^2+(16)^2+(5)^2}=15 \sqrt 2$ Thus, $d=\dfrac{15 \sqrt 2}{5 \sqrt 2}=3$