Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.1 - Three-Dimensional Coordinate Systems - Exercises 12.1 - Page 696: 54


$x^2+(y +7)^2+z^2=49$

Work Step by Step

As we know the standard equation of sphere is $(x-a)^2+(y-b)^2+(z-c)^2=r^2$ ...(a) where $(a,b,c)$ represents center and radius of the sphere is $r$ Plug $a=0,b=-7,c=0, r=7$ in equation (a). Thus, we have $(x - 0)^2+(y -(-7))^2+(z -0)^2=(7)^2$ or, $x^2+(y +7)^2+z^2=49$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.