Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.1 - Three-Dimensional Coordinate Systems - Exercises 12.1 - Page 696: 26

Answer

$x=3,y=-1,z=2$

Work Step by Step

Let us consider a point $(a,b,c)$ on the plane. When the plane passing through the point $(a,b,c)$ and perpendicular to the $x-axis, y-axis$, and $z-axis$, this means that we have $x=a,y=b$ and $z=c$ Here, we get $x=3,y=-1,z=2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.