## Thomas' Calculus 13th Edition

$x=3,y=-1,z=2$
Let us consider a point $(a,b,c)$ on the plane. When the plane passing through the point $(a,b,c)$ and perpendicular to the $x-axis, y-axis$, and $z-axis$, this means that we have $x=a,y=b$ and $z=c$ Here, we get $x=3,y=-1,z=2$