Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.1 - Three-Dimensional Coordinate Systems - Exercises 12.1 - Page 696: 27

Answer

$x=1,y=-3,z=-1$

Work Step by Step

Let us consider a point $(a,b,c)$ on the plane. When the plane passing through the point $(a,b,c)$ and perpendicular to the $x-axis, y-axis$, and $z-axis$, this means that we have $x=a,y=b$ and $z=c$ Here, we get $x=1,y=-3,z=-1$
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