Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.1 - Three-Dimensional Coordinate Systems - Exercises 12.1 - Page 696: 46

Answer

$\sqrt{38}$

Work Step by Step

Formula to find the distance between two points is $|PQ|=\sqrt{(x-x_0)^2+(y-y_0)^2+(z-z_0)^2}$ Let us consider $P=(5,3,-2)$ and $Q=(0,0,0)$ Now, $|PQ|=\sqrt{(0-5)^2+(0-3)^2+(0-(-2))^2}=\sqrt{(-5)^2+(-3)^2+(2))^2}$ or, $|PQ|=\sqrt {25+9+4}=\sqrt{38}$
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