Answer
$(x + 1)^2+(y -\dfrac{1}{2})^2+(z+ \dfrac{2}{3})^2=\dfrac{16}{81}$
Work Step by Step
As we know the standard equation of sphere is $(x-a)^2+(y-b)^2+(z-c)^2=r^2$ ...(a)
where $(a,b,c)$ represents center and radius of the sphere is $r$
Plug $a_0=-1,b=\dfrac{1}{2},c=\dfrac{-2}{3}, r=\dfrac{4}{9}$
in equation (a).
Thus, we have $(x - (-1))^2+(y -(\dfrac{1}{2}))^2+(z - (\dfrac{-2}{3}))^2=(\dfrac{4}{9})^2$
or, $(x + 1)^2+(y -\dfrac{1}{2})^2+(z+ \dfrac{2}{3})^2=\dfrac{16}{81}$
