## Thomas' Calculus 13th Edition

Center$(\sqrt 2, \sqrt 2. -\sqrt 2)$ and radius is $\sqrt 2$
As we know the standard equation of sphere is $(x-a)^2+(y-b)^2+(z-c)^2=r^2$ where $(a,b,c)$ represents center and radius of the sphere is $r$ Now, $(x - \sqrt 2)^2+(y -\sqrt 2)^2+(z + \sqrt 2)^2=2$ $\implies (x - \sqrt 2)^2+(y -\sqrt 2)^2+(z - (-\sqrt 2))^2=(\sqrt 2)^2$ Compare this equation with the standard equation of sphere. Thus, Center$(\sqrt 2, \sqrt 2. -\sqrt 2)$ and radius is $\sqrt 2$