Answer
Center$(\sqrt 2, \sqrt 2. -\sqrt 2)$ and radius is $\sqrt 2$
Work Step by Step
As we know the standard equation of sphere is $(x-a)^2+(y-b)^2+(z-c)^2=r^2$
where $(a,b,c)$ represents center and radius of the sphere is $r$
Now, $(x - \sqrt 2)^2+(y -\sqrt 2)^2+(z + \sqrt 2)^2=2$
$\implies (x - \sqrt 2)^2+(y -\sqrt 2)^2+(z - (-\sqrt 2))^2=(\sqrt 2)^2$
Compare this equation with the standard equation of sphere.
Thus,
Center$(\sqrt 2, \sqrt 2. -\sqrt 2)$ and radius is $\sqrt 2$
