Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Practice Exercises - Page 734: 37



Work Step by Step

The standard equation of a plane passing through the point $(x_1,y_1,z_1)$ can be defined as: $a(x-x_1)+b(y-y_1)+c(z-z_1)=0$ The normal vector to the plane is given by:$n=\lt -9,1,7 \gt$ Thus, $-9(x -1)+1(y +1)+7(z-2)=0 \implies -9x+9+y+1+7z-14=0$ or, $-9x+y+7z=4$
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