Answer
$\sqrt {14}$
Work Step by Step
The distance formula for two vectors $p$ and $q$ is defined as:
$d=\dfrac{|p \cdot q|}{|p|}$
Thus, we have $p \cdot q=(-2)(2)+(0)(3)+(-10)(1)=-14$
and $|p \cdot q|=|-14|=14$
Thus, $d=\dfrac{14}{ \sqrt {(2)^2+(3)^2+(1)^2}}=\dfrac{14}{\sqrt {14}}=\sqrt {14}$
