Answer
$\lt 6,-8 \gt$ and $10$
Work Step by Step
The magnitude of a vector can be calculated as:
$|v|=\sqrt{v_1^2+v_2^2}$
Now,$-2u=-2\lt -3,4 \gt =\lt 6,-8 \gt$
and $|\lt 6,-8\gt|=\sqrt{(6)^2+(-8)^2}=\sqrt {100}=10$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 12: Vectors and the Geometry of Space - Practice Exercises - Page 734: 3
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