Answer
$\lt -1,-1 \gt$ and $\sqrt {2}$
Work Step by Step
The magnitude of a vector can be calculated as:
$|v|=\sqrt{v_1^2+v_2^2}$
Now,$u+v=\lt -3,4 \gt + \lt 2,-5 \gt =\lt -1,-1 \gt$
and $|\lt -1,-1\gt|=\sqrt{(-1)^2+(-1)^2}=\sqrt {2}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 12: Vectors and the Geometry of Space - Practice Exercises - Page 734: 2
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
