Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Practice Exercises - Page 734: 36



Work Step by Step

The standard equation of a plane passing through the point $(x_1,y_1,z_1)$ can be defined as: $a(x-x_1)+b(y-y_1)+c(z-z_1)=0$ The normal vector to the plane is given by:$n=\lt 1,-2,3 \gt$ Thus, $1(x+1)-2(y -6)+3(z-0)=0 \implies x+1-2y+12+3z=0$ or, $x-2y+3z=-13$
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