Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1 - Page 12: 54

Answer

The function is odd.

Work Step by Step

$g(x)=\frac{x}{x^2-1}$ $g(-x)=\frac{-x}{(-x)^2-1}=-\frac{x}{x^2-1}$ $-g(x)=-\frac{x}{x^2-1}$ $g(x)\neq g(-x)$ - The function is not even. $g(-x)= -g(x)$ - The function is odd.
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