Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1 - Page 12: 52

Answer

The function is even.

Work Step by Step

$g(x)=x^4+3x^2-1$ $g(-x)=(-x)^4+3(-x)^2-1=x^4+3x^2-1$ $-g(x)=-x^4-3x^2+1$ $g(x)=g(-x)$ - The function is even. $g(-x)\neq -g(x)$ - The function is not odd.
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