Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1 - Page 12: 50

Answer

The function is neither even nor odd.

Work Step by Step

$f(x)=x^2+x$ $f(-x)=(-x)^2-x=x^2-x$ $-f(x)=-x^2-x$ $f(x)\ne f(-x)$ - The function is not even. $f(-x)\ne-f(x)$ - The function is not odd.
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