Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1 - Page 12: 26

Answer

See graph

Work Step by Step

$g(0) = 1 - 0$ $g(0) = 1 $ $g(1) = 1 - 1$ $g(1) = 0$ So the first part of the graph will be a straight line from ($0,1)$ to $(1,0)$ $g(1) = 2 - 1$ $g(1) = 1$ $g(2) = 2 - 2$ $g(2) = 0$ So the second part of the graph will be a straight line from (but not including) $(1,1)$ to $(2,0)$.
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