## Thomas' Calculus 13th Edition

The first part of the graph is $\frac{1}{x}$ between both asymptotes x=0 and y=0. The second part of the graph is the linear graph x from (0,0) on.
$G(0) = \frac{1}{0}$, which is impossible. So x = 0 is an asymptote of $\frac{1}{x}$. The other asymptote of $\frac{1}{x}$ is y = 0, which is obtained by substituting a very big negative value of x. Thus the first part of the graph will be $\frac{1}{x}$ between both asymptotes x=0 and y=0. $G(0) = {0}$ $G(1) = {1}$ So the second part of the graph will be the linear graph x from (0,0) on.