Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1 - Page 12: 49


The function is even.

Work Step by Step

$f(x)=x^2+1$ $f(-x)=(-x)^2+1=x^2+1$ $f(x)=f(-x)$ - The function is even. $f(-x)\neq-f(x)$ The function is not odd.
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