## Thomas' Calculus 13th Edition

$(-2,-9)$
We find the second pair of coordinates: $A(x_{1},y_{1})=\quad$... $B(x_{2},y_{2})=(3,-3)\quad$ $\left\{\begin{array}{l} \Delta x=x_{2}-x_{1}=5\\ \Delta y=y_{2}-y_{1}=6 \end{array}\right.$ $\left\{\begin{array}{l} x_{1}=x_{2}-\Delta x=3-5=-2\\ \\ y_{1}=y_{2}-\Delta y=-3-6=-9 \end{array}\right.$ $A(x_{1},y_{1})=(-2,-9)$