#### Answer

$y=4x+4$

#### Work Step by Step

The line contains points
$(x_{1},y_{1})=(0,4),\quad $(the y-intercept)
$(x_{2},y_{2})=(-1,0),\quad $(the x-intercept)
We calculate the increments,
$\left\{\begin{array}{l}
\Delta x=x_{2}-x_{1}=-1-0=-1\\
\Delta y=y_{2}-y_{1}=0-4=-4
\end{array}\right.$
Since $\Delta x\neq 0$, the slope is defined,
$\displaystyle \qquad m=\frac{\Delta y}{\Delta x}=\frac{-4}{-1}=4$
The slope-intercept form a line equation is
$y=mx+b,$ where $m$ = slope and $b$ = y-intercept.
Here, $m=4$ and $b=4$
$y=4x+4$