Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Appendices - Section A.3 - Lines, Circles, and Parabolas - Exercises A.3 - Page AP-17: 2


$\left\{\begin{array}{l} \Delta x=-4.9\\ \Delta y=0 \end{array}\right., \qquad $distance = $4.9$

Work Step by Step

$A=(x_{1},y_{1})=(-3.2, \ -2)$ $B=(x_{2},y_{2})=(-8.1, \ -2)$ The increments in the coordinates are calculated as $\left\{\begin{array}{l} \Delta x=x_{2}-x_{1}\\ \Delta y=y_{2}-y_{1} \end{array}\right.$ $\left\{\begin{array}{l} \Delta x=-8.1-(-3.2)=-4.9\\ \\ \Delta y=-2-(-2)=0 \end{array}\right.$ The distance formula: $\quad d=\sqrt{(\Delta x)^{2}+(\Delta y)^{2}}$ $d=\sqrt{(-4.9)^{2}+(0)^{2}}=\sqrt{(4.9)^{2}}=4.9$
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