Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Appendices - Section A.3 - Lines, Circles, and Parabolas - Exercises A.3 - Page AP-17: 17

Answer

x-intercept: $\quad \sqrt{3}$ y-intercept: $\quad -\sqrt{2}$ .
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Work Step by Step

The x-intercept is the value at which the graph crosses the x-axis (the y-coordinate is 0) $\sqrt{2}x-\sqrt{3}(0)=\sqrt{6}$ $\sqrt{2}x=\sqrt{6}$ $x=\sqrt{\frac{6}{2}}=\sqrt{3}$ The y-intercept is the value at which the graph crosses the y-axis (the y-coordinate is 0) $\sqrt{2}(0)-\sqrt{3}y=\sqrt{6}$ $-\sqrt{3}y=\sqrt{6}$ $y=-\sqrt{\frac{6}{3}}=-\sqrt{2}$ Draw a line through $(\sqrt{3},0)$ and $(0,-\sqrt{2}).$
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