## Thomas' Calculus 13th Edition

x-intercept: $\quad \sqrt{3}$ y-intercept: $\quad -\sqrt{2}$ .
The x-intercept is the value at which the graph crosses the x-axis (the y-coordinate is 0) $\sqrt{2}x-\sqrt{3}(0)=\sqrt{6}$ $\sqrt{2}x=\sqrt{6}$ $x=\sqrt{\frac{6}{2}}=\sqrt{3}$ The y-intercept is the value at which the graph crosses the y-axis (the y-coordinate is 0) $\sqrt{2}(0)-\sqrt{3}y=\sqrt{6}$ $-\sqrt{3}y=\sqrt{6}$ $y=-\sqrt{\frac{6}{3}}=-\sqrt{2}$ Draw a line through $(\sqrt{3},0)$ and $(0,-\sqrt{2}).$