Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 13 - Section 13.1 - The Indefinite Integral - Exercises - Page 960: 67b

Answer

$t=3$ hours

Work Step by Step

If $s(t)=1800$ $ 1800=525t+25t^{2}\qquad$ divide with 25 $72=21t+t^{2}$ $t^{2}+21t-72=0$ $(t+24)(t-3)=0$ Discarding the negative solution $(-24$ h), $t=3$ hours
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