Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 13 - Section 13.1 - The Indefinite Integral - Exercises - Page 960: 64

Answer

$310\ \ \mathrm{f}\mathrm{t}/\mathrm{s}$ downward.

Work Step by Step

Define "up" as the positive direction of motion. Acceleration is the derivative of velocity $a(t)=v'(t)=-32\ \ \mathrm{f}\mathrm{t}/\mathrm{s}^{2}$ $v(t)=\displaystyle \int(-32)dt=-32t+C.$ To find C, use the given information: $v(0)=10$ $v(t)=-32t+C$ $10=0+\mathrm{C}$ $C=10$ Thus, $v(t)=-32t+10 \ \ \mathrm{f}\mathrm{t}/\mathrm{s}$ After 10 seconds, $v(10)=-32(10)+10=-310$ The stone is traveling $310\ \ \mathrm{f}\mathrm{t}/\mathrm{s}$ downward.
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