Answer
$s(t)=3e^{t}+\displaystyle \frac{t^{2}}{2}+C$
Work Step by Step
The function of velocity is the derivative of $s(t),$ the function of position.
$v(t)=s'(t)=3e^{t}+t$
$s(t)=\displaystyle \int(3e^{t}+t)dt$
$=3e^{t}+\displaystyle \frac{t^{2}}{2}+C$
This is a collection of functions.
Further information is needed to find C.
