## Finite Math and Applied Calculus (6th Edition)

$\displaystyle \frac{2}{3}\cdot x^{1.2}-\frac{1}{3}\cdot x^{2.1}$
An expression is in exponent form if * there are no radicals and * all powers of unknowns occur in the numerator. All terms in a sum or difference are of the form: (constant)(expression with x$)^{p}$ ----------------- For the first term (x in the denominator) we use $a^{-n}=\displaystyle \frac{1}{a^{n}}=(\frac{1}{a})^{n}$ so $\displaystyle \frac{2}{3x^{-1,2}}$ becomes $\displaystyle \frac{2}{3}x^{-(-1.2)}=\frac{2}{3}\cdot x^{1.2}$ the second term is $\displaystyle \frac{1}{3}\cdot x^{2.1}$ The expression, in exponent form is $\displaystyle \frac{2}{3}\cdot x^{1.2}-\frac{1}{3}\cdot x^{2.1}$