Answer
By the formulas given on page eight and nine,
$\frac{x^2yz^2}{(xyz^{-1})^{-1}} = x^3y^2z$.
Work Step by Step
By the formulas given on page eight and nine,
$\frac{x^2yz^2}{(xyz^{-1})^{-1}} = \frac{x^2yz^2}{x^{-1}y^{-1}z^{(-1)\times(-1)}} = \frac{x^2yz^2}{x^{-1}y^{-1}z} = x^{2-(-1)}y^{1 - (-1)}z^{2-1}= x^3y^2z$.
