Answer
$(\frac{-2}{3})^{-2} = \frac{9}{4}$
Work Step by Step
$(\frac{-2}{3})^{-2} = \frac{1}{(\frac{-2}{3})^2} = \frac{1}{\frac{(-2)^2}{3^2}} = \frac{1}{\frac{4}{9}} = \frac{9}{4}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 10
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