Answer
$\frac{x^{-1}y^1}{x^2y^2} = \frac{1}{x^3y} $
Work Step by Step
By the formulas given on page eight and nine,
$\frac{x^{-1}y^1}{x^2y^2} = x^{(-1-2)} y^{1-2} = x^{-1-2}y^{-1} = x^{-3}y^{-1}= \frac{1}{x^3}\frac{1}{y^1}= \frac{1}{x^3y} $.
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 24
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