Answer
$-x^2x^{-3}y = -\frac{y}{x}$
Work Step by Step
By the formulas given on page eight and nine,
$-x^2x^{-3}y = -x^{2+(-3)}y = -x^{2-3} y = -x^{-1}y = -\frac{1}{x^1}y = -\frac{y}{x}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 19
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