Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 23

Answer

$\frac{x^2y^2}{x^{-1}y} = x^3y$

Work Step by Step

By the formulas given on page eight and nine, $\frac{x^2y^2}{x^{-1}y} = x^{2-(-1)} y^{2-1} = x^{2+1}y^1 = x^3y$.
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