Answer
$\frac{3}{4}x^{\frac{2}{5}}-\frac{7}{2}x^{-\frac{3}{2}}$
Work Step by Step
$\frac{3\sqrt[5] x^{2}}{4}-\frac{7}{2\sqrt x^{3}}=\frac{3x^{\frac{2}{5}}}{4}-\frac{7}{2x^{\frac{3}{2}}}=\frac{3}{4}x^{\frac{2}{5}}-\frac{7}{2}\times\frac{1}{x^{\frac{3}{2}}}=\frac{3}{4}x^{\frac{2}{5}}-\frac{7}{2}x^{-\frac{3}{2}}$
