## Calculus with Applications (10th Edition)

$-2$ and $-3$
See example 2 in R-2 (factoring trinomials). We search for factors of 6 that add up to 5 .... 2$\times$3=6, 2+3=5 so $x^{2}+5x+6=0$ $(x+2)(x+3)=0$ We apply the zero product rule (if the product is zero, at least one of the factors is zero) $x=-2 \ \$ or $\ \ x=-3$ solutions: $-2\ \$ and $-3$