Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.4 Equations - R.4 Exercises - Page R-16: 24


$\text{No real solutions.}$

Work Step by Step

$2x^{2}-7x+30=0$ Use the quadratic formula: (For $ax^{2}+bx+c=0,\ x=\displaystyle \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$ ) $x=\displaystyle \frac{-(-7)\pm\sqrt{(-7)^{2}-4(2)(30)}}{2(2)}$ $x=\displaystyle \frac{7\pm\sqrt{49-240}}{4}$ $x=\displaystyle \frac{7\pm\sqrt{-191}}{4}$ $\sqrt{-191}$ is not a real number. ( there is no real number whose square is $-191$) (squares of real numbers can not be negative) Therefore, there are no real solutions.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.