## Calculus with Applications (10th Edition)

The aim is,step by step, to isolate x on one side of the equation. Subtract x from both sides and the RHS will have no x's Subtract 8 from both sides and the LHS will contain only x's. $2x+8=x-4\qquad/-x-8$ $2x-x=-4-8\qquad$... simplify $x=-12 \qquad$(solution: $-12)$