Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.4 Equations - R.4 Exercises - Page R-16: 8


$- \displaystyle \frac{10}{19}$

Work Step by Step

The aim is, step by step, to isolate p on one side of the equation. ...Multiply out the parentheses, starting with the innermost, $-(3-p)=-3+p,$ working our way outwards: $ 4[2p-3+p+5]=-7p-2\qquad$ ... simplify $ 4(3p+2)=-7p-2\qquad$ ... multiply $12p+8=-7p-2$ ...Subtracting $8$ from both sides removes it from the $LHS$ ...Adding $7p$ to both sides removes it from the $RHS$ $12p+8=-7p-2\qquad .../+7p-8$ $ 12p+7p=-2-8\qquad$ ... simplify $19p=-10$ ...Dividing both sides with $19$ isolates $p$ on the LHS. $p=- \displaystyle \frac{10}{19}$
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