## Calculus with Applications (10th Edition)

$- \displaystyle \frac{10}{19}$
The aim is, step by step, to isolate p on one side of the equation. ...Multiply out the parentheses, starting with the innermost, $-(3-p)=-3+p,$ working our way outwards: $4[2p-3+p+5]=-7p-2\qquad$ ... simplify $4(3p+2)=-7p-2\qquad$ ... multiply $12p+8=-7p-2$ ...Subtracting $8$ from both sides removes it from the $LHS$ ...Adding $7p$ to both sides removes it from the $RHS$ $12p+8=-7p-2\qquad .../+7p-8$ $12p+7p=-2-8\qquad$ ... simplify $19p=-10$ ...Dividing both sides with $19$ isolates $p$ on the LHS. $p=- \displaystyle \frac{10}{19}$