Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.4 Equations - R.4 Exercises - Page R-16: 14


5 and 2

Work Step by Step

Set the $RHS$ to 0 by adding 10 to both sides $m(m-7)=-10\qquad.../$+10 $m^{2}-7m+10=0$ To factor the trinomial, we search for factors of +10,\ whose sum is -7$:\qquad $ We find $-5$ and $-2$. Our equation becomes $(m-5)(m-2)=0$ By the zero product principle, $m-5=0$ or $m-2=0$ $m=5$ or $m=2$ The solutions are 5 and 2.
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