Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.4 Equations - R.4 Exercises - Page R-16: 27


The solution is $x=3$

Work Step by Step

$\dfrac{3x-2}{7}=\dfrac{x+2}{5}$ Take $7$ to multiply the right side and $5$ to multiply the left side (cross multiplication): $5(3x-2)=7(x+2)$ $15x-10=7x+14$ Take $7x$ to the left side and $10$ to the right side: $15x-7x=14+10$ $8x=24$ Take $8$ to divide the right side: $x=\dfrac{24}{8}$ $x=3$
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