Calculus with Applications (10th Edition)

The solution is $x=3$
$\dfrac{3x-2}{7}=\dfrac{x+2}{5}$ Take $7$ to multiply the right side and $5$ to multiply the left side (cross multiplication): $5(3x-2)=7(x+2)$ $15x-10=7x+14$ Take $7x$ to the left side and $10$ to the right side: $15x-7x=14+10$ $8x=24$ Take $8$ to divide the right side: $x=\dfrac{24}{8}$ $x=3$