Answer
$0$ and $4$
Work Step by Step
Divide the equation by 12,
$12y^{2}-48y=0\qquad.../\div 12$
$ y^{2}-4y=0\qquad$ ... factor out y
$y(y-4)=0$
By the zero product principle,
$y=0$ or $y-4=0$
$y=0$ or $y=4$
The solutions are $0$ and $4$.
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter R - Algebra Reference - R.4 Equations - R.4 Exercises - Page R-16: 17
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