Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.4 Equations - R.4 Exercises - Page R-16: 17


$0$ and $4$

Work Step by Step

Divide the equation by 12, $12y^{2}-48y=0\qquad.../\div 12$ $ y^{2}-4y=0\qquad$ ... factor out y $y(y-4)=0$ By the zero product principle, $y=0$ or $y-4=0$ $y=0$ or $y=4$ The solutions are $0$ and $4$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.