Answer
$$
y=\frac{2x}{x-3}
$$
We find that:
Asymptotic: $y=2$ and $x=3$
$x$-intercept: 0
$y$ -intercept: 0
Work Step by Step
$$
y=\frac{2x}{x-3}
$$
The function is undefined for $x=3$, so the line $x=3$ is a vertical asymptotic..
To find a horizontal asymptotic, let $x$ get larger and larger, so that
$$
y=\lim _{x \rightarrow \infty} \frac{2x}{x-3}=2
$$
This means that the line $y=2 $ is a horizontal asymptotic.
When $x=0 $ the $y$-intercept is 0
When $y=0 $ the $x$-intercept is 0
So,
Asymptotic: $y=2$ and $x=3$
$x$-intercept: 0
$y$ -intercept: 0
