Answer
$$
y=\frac{-1}{x+3}
$$
The function is undefined for $x=-3$, so the line $x=-3$ is a vertical asymptotic..
To find a horizontal asymptotic, let $x$ get larger and larger, so that
$$
y=\lim _{x \rightarrow \infty}\frac{-1}{x+3}=0
$$
This means that the line $y=0 $ is a horizontal asymptotic.
When $x=0 $ the y-intercept is $ -\frac{1}{3}$
Work Step by Step
$$
y=\frac{-1}{x+3}
$$
The function is undefined for $x=-3$, so the line $x=-3$ is a vertical asymptotic..
To find a horizontal asymptotic, let $x$ get larger and larger, so that
$$
y=\lim _{x \rightarrow \infty}\frac{-1}{x+3}=0
$$
This means that the line $y=0 $ is a horizontal asymptotic.
When $x=0 $ the y-intercept is $ -\frac{1}{3}$