Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.3 Polynomial and Rational Functions - 2.3 Exercises - Page 75: 25

Answer

Because the range is $(-\infty, \infty)$ this must be a polynomial of odd degree. * Notice that it has six turning points and we know that a polynomial of degree $n$ has at most $n-1$ turning points. So the polynomial graphed in the Figure might be degree $7$, although it could also be of degree $9, 11,$ etc. * Finally, notice also that the polynomial becomes a large negative number as $x$ becomes a large positive number, so the leading coefficient must be negative sign.

Work Step by Step

Because the range is $(-\infty, \infty)$ this must be a polynomial of odd degree. * Notice that it has six turning points and we know that a polynomial of degree $n$ has at most $n-1$ turning points. So the polynomial graphed in the Figure might be degree $7$, although it could also be of degree $9, 11,$ etc. * Finally, notice also that the polynomial becomes a large negative number as $x$ becomes a large positive number, so the leading coefficient must be negative sign.
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