Answer
$$
y=\frac{-4}{x+2}
$$
The function is undefined for $x=-2$, so the line $x=-2$ is a vertical asymptotic..
To find a horizontal asymptotic, let $x$ get larger and larger, so that
$$
y=\lim _{x \rightarrow \infty} \frac{-4}{x+2} =0
$$
This means that the line $y=0 $ is a horizontal asymptotic.
When $x=0 $ the y-intercept is -2
Work Step by Step
$$
y=\frac{-4}{x+2}
$$
The function is undefined for $x=-2$, so the line $x=-2$ is a vertical asymptotic..
To find a horizontal asymptotic, let $x$ get larger and larger, so that
$$
y=\lim _{x \rightarrow \infty} \frac{-4}{x+2} =0
$$
This means that the line $y=0 $ is a horizontal asymptotic.
When $x=0 $ the y-intercept is -2
