Answer
$$
y=\frac{2}{3+2x}
$$
We find that:
Asymptotic : $ y=0 $ and $x=-\frac{3}{2}$
$x$-intercept: non
$y$-intercept: $\frac{2}{3}$
Work Step by Step
$$
y=\frac{2}{3+2x}
$$
The function is undefined for $x=-\frac{3}{2}$, so the line $x=-\frac{3}{2}$, is a vertical asymptotic..
To find a horizontal asymptotic, let $x$ get larger and larger, so that
$$
y=\lim _{x \rightarrow \infty} \frac{2}{3+2x}=0
$$
This means that the line $y=0 $ is a horizontal asymptotic.
When $x=0 $ the y-intercept is $\frac{2}{3}$.
So ,
Asymptotic : $ y=0 $ and $x=-\frac{3}{2}$
$x$-intercept: non
$y$-intercept: $\frac{2}{3}$