Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 15 - Section 15.2 - Double Integrals over General Regions - 15.2 Exercise - Page 1009: 45

Answer

$$\iint_{D} f(x,y) dA=\int_{0}^{1} \int_{x}^{1} f(x,y) \ dy \ dx$$

Work Step by Step

We can define the domain $D$ in the Type-1 using the vertical cross-sections as follows: $ D=\left\{ (x, y) | x \leq y \leq 1, \ 0 \leq x \leq 1 \right\} $ and we can define the domain $D$ in the Type-II using the horizontal cross-sections as follows: $ D=\left\{ (x, y) | 0 \leq x \leq y, \ 0 \leq y \leq 1 \right\} $ Therefore, $$\iint_{D} f(x,y) dA=\int_{0}^{1} \int_{x}^{1} f(x,y) \ dy \ dx$$
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