## Calculus: Early Transcendentals 8th Edition

As a result $f(-3)=-1, f(0)=-1, f(2)=3$.
$f(x)=-1$ for $x\leq1$ and $f(x)=7-2x$ for $x\gt1$ $f(-3)=-1\Rightarrow f(-3)=-1$ $f(0)=-1\Rightarrow f(0)=-1$ $f(2)=7-2(2)\Rightarrow f(2)=3$