Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises - Page 21: 42

$f(-3)=\frac{9}{2}, f(0)=3, f(2)=-1$.

$f(x)=3-\frac{x}{2}$ for $x\lt2$ and $f(x)=2x-5$ for $x\geq2$ $f(-3)=3-\frac{-3}{2}\Rightarrow f(-3)=\frac{9}{2}$ $f(0)=3-\frac{0}{2}\Rightarrow f(0)=3$ $f(2)=2(2)-5\Rightarrow f(2)=-1$