Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises: 35


$x\lt0$ or $x\gt5$

Work Step by Step

$\because h(x)$ is defined for all real x where the denominator is not equal to zero $[\sqrt[4] (x^{2}-5x)\ne0, x^{2}-5x\ne0$], and only the fourth root of non-negative numbers is real $[x^{2}-5x\geq0]$ $\therefore x^{2}-5x\gt0,$ $x(x-5)\gt0,$ $x\lt0$ or $x\gt5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.