Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises - Page 21: 40

Answer

The domain of $g(t)$ is: $(-∞,-1) \cup (-1,∞)$
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Work Step by Step

$g(t) = \frac{t^{2} - 1}{t + 1}$ has one restriction at $t = -1$ (undefined). Otherwise, it becomes a line: $g(t)=\frac{(t+1)(t-1)}{(t+1)}=t-1$
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